For positive integer X, write X=Σₙ₌₁^X1 and X²=Σₙ₌₁^X(2n−1). Taking expectations via nonnegative sums gives A,D. The transform F(X) has generally unequal point masses, so B fails. Full support on every positive integer gives positive probability X>1, whereas 1/X≤1; hence C fails. If “support” meant only that X takes values in this set, the degenerate X=1 would change C; the official **A,D** uses full support.
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