The variance in I is 5Σi²/(2n+1)²=5n(n+1)/[6(2n+1)]. Equating to 1 gives (5n+3)(n−2)=0, so positive integer n=2. In II, Φ of the standardized normal is uniform(0,1), and −ln U is exponential of mean 1, whose third moment is 3!=6. Both true, **C**.
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