Calls arrive as a rate-one Poisson process per minute. Choose five two-minute intervals. Let p be the probability each interval has at most one call. Find e¹⁰p as an integer.
Each two-minute count is Poisson(2),so P(count≤1)=e⁻²(1+2)=3e⁻². For independent interval counts,p=(3e⁻²)⁵=243e⁻¹⁰,thus **243**. Independence requires nonoverlapping intervals;this is implicit in the official calculation though the source only says the intervals are chosen at random.
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