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GATE 2021 ST – Question 38

Calculus · Single Variable Calculus · 2 marks · Multiple choice

A differentiable f:ℝ→ℝ satisfies f(0)=0 and f′(x)+2f(x)>0 for all x. Which holds?

  1. f(x)>0 for x>0 and f(x)<0 for x<0.
  2. f(x)<0 for every x≠0.
  3. f(x)>0 for every x≠0.
  4. f(x)<0 for x>0 and f(x)>0 for x<0.

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Correct answer: (A) f(x)>0 for x>0 and f(x)<0 for x<0.

Explanation

Set g(x)=e^(2x)f(x). Then g′=e^(2x)(f′+2f)>0 everywhere,so g is strictly increasing and g(0)=0. Therefore g and hence f are positive to the right and negative to the left of zero. **A**.

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