Bulk unit weight is $\gamma=(G_s+Se)\gamma_w/(1+e)$. Here $(2.7+.9(.8))/(1.8)=1.9$. Therefore $\gamma=1.9(9810)=\mathbf{18639}$ N/m³, **B**. Option C expresses approximately the same magnitude in kN/m³, not the requested N/m³.
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