Subtract the first equation from the second: $x+3y=68$. The first gives $z=34-x+2y$. Substitute into the third to get $4x-5y=119$. Using $x=68-3y$ gives $272-17y=119$,so $y=9,x=41,z=11$. Their sum is **61.00**. These values satisfy all three original equations.
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