A 10 MLD aerobic plant operates at 80% capacity. Inlet/outlet BOD100/30 mg/L;observed biomass yield .5 g VSS/g BOD. Find sludge production in kg/day, to one decimal.
Actual flow=8×10⁶ L/day and removed BOD=70 mg/L. Removed mass=$8\times10^6(70)/10^6=560$ kg/day. Biomass production=.5(560)=**280.0 kg VSS/day**. Observed yield already represents net produced biomass.
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