A cylindrical tissue has diameter 2 cm,height 3 cm,Young’s modulus 20 MPa. Under axial tensile force 10 N, find the percentage height increase to two decimals, using linear axial elasticity.
Cross-sectional area is π(0.01 m)². Axial strain is F/(EA)=10/[20×10⁶×π×10⁻⁴]≈0.00159155. Percentage height change is one hundred times strain, about 0.159155%, rounded to 0.16%. The original height cancels from the fractional change.
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