An airplane has angle of attack 3° and velocity components 300 km/h horizontally and 15.72 km/h vertically upward. Find its pitch angle in degrees (nearest integer).
The flight-path angle is $\gamma=\tan^{-1}(15.72/300)\simeq3.00°$. Pitch angle is the orientation of the reference axis relative to horizontal: θ=α+γ=3°+3°=6°. The vertical component is positive, so the flight-path angle is added.
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