Uniform incompressible potential flow past a circular cylinder of radius R has $u_r=U(1-R^2/r^2)\cos\theta$ and $u_\theta=-U(1+R^2/r^2)\sin\theta$. At what first-quadrant surface angle θ, in degrees, is the pressure coefficient zero?
At r=R, radial velocity is zero and tangential speed is 2U sinθ. Bernoulli gives $C_p=1-(V/U)^2=1-4\sin^2\theta$. Setting this to zero gives sinθ=1/2. The first-quadrant angle is 30°.
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