Heating 25 mg of a hydrated compound of molar mass 250 g/mol leaves 16 mg of dehydrated compound. How many water molecules are lost per formula unit? Water molar mass is 18 g/mol.
Water loss is 25−16=9 mg, corresponding to 0.009/18=0.0005 mol. Initial hydrate amount is 0.025/250=0.0001 mol. The ratio is 0.0005/0.0001=5, so five water molecules are lost per hydrate formula unit.
More Instrumental Methods of Analysis: UV-visible, fluorescence and FT-IR spectrophotometry, NMR and ESR spectroscopy, mass spectrometry, atomic absorption spectroscopy, Mössbauer spectroscopy (Fe and Sn) and X- ray crystallography. Electroanalytical methods – cyclic voltammetry, ion-selective electrodes. Thermo-analytical methods: TGA, DTA and DSC. questions
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