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GATE 2020 PI – Question 22

General Engineering · Thermal and Fluids Engineering · 1 mark · Multiple choice

A Carnot engine receives600 kJ/cycle from627°C and rejects heat to27°C. Find rejected heat per cycle in kJ (nearest integer).

  1. 26
  2. 200
  3. 400
  4. 574

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Correct answer: (B) 200

Explanation

For a reversible Carnot cycle, Qc/Qh=Tc/Th using absolute temperatures. Tc≈300 K and Th≈900 K, so Qc=600(300/900)=200 kJ, B. Celsius temperatures cannot be used directly in this ratio.

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