Mining Methods and Machinery · Mining Machinery · 1 mark · Numerical answer
The belt has tight-side tension5.0 kN and slack-side tension2.5 kN as shown. Friction coefficient is0.3. At limiting no-slip equilibrium, find wrap angle θ in degrees, to two decimals.
The capstan relation is T₁/T₂=e^(μθ) with θ in radians. Thus θ=ln(5/2.5)/0.3=2.31049 rad=132.38°. The source’s intended calculation uses limiting friction; without that limiting condition no-slip alone specifies a minimum wrap rather than a unique angle.
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