GATE 2025 MN – Question 13
For $y=x^x$ with x>0, find dy/dx.
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Correct answer: (A) $x^x(\ln x+1)$
Explanation
Take logarithms: ln y=x ln x. Differentiate to get y′/y=ln x+1. Multiplying by y=xˣ yields xˣ(ln x+1), A. The usual constant-power rule alone does not apply because both the base and exponent vary.