For the rectangular-bend correlation use $X=0.25(\theta/90)^2/(m^2\sqrt a)$, where m=r/b and a=d/b. Here m=4/2=2, a=2.5/2=1.25 and θ=45°. Therefore X=0.25×0.5²/(4√1.25)=0.013975≈0.014, A. The deflection must be converted to degrees for this form of the correlation.
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