Mining Methods and Machinery · Mining Machinery · 1 mark · Numerical answer
A friction-winder skip accelerates from rest to its steady speed in 15 s. Use the given torque-time diagram to find deceleration time in seconds, to one decimal.
The steady-speed torque 50 kN·m balances resistance. During acceleration, net torque is 70−50=20 kN·m; during deceleration its magnitude is 50−20=30 kN·m. The angular-momentum changes have equal magnitudes, so 20×15=30×td. Hence td=10.0 s. Use net torque rather than the plotted total drive torque.
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