GATE 2022 EE – Question 41
Let $f(x)=\int_0^xe^t(t-1)(t-2)\,dt$. Then $f(x)$ decreases in the interval
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Correct answer: (A) $x\in(1,2)$
Explanation
$f'(x)=e^x(x-1)(x-2)$. Since $e^x>0$, $f'<0$ exactly when $(x-1)(x-2)<0$, i.e. for $1<x<2$.