GATE 2020 EE – Question 37
The vector function expressed by
$$\mathbf F=\mathbf a_x(5y-k_1z)+\mathbf a_y(3z+k_2x)+\mathbf a_z(k_3y-4x)$$
represents a conservative field, where $\mathbf a_x$, $\mathbf a_y$, $\mathbf a_z$ are unit vectors along x, y and z directions, respectively. The values of constants $k_1,k_2,k_3$ are given by:
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Correct answer: (C) $k_1=4,k_2=5,k_3=3$
Explanation
A conservative field is irrotational, so $\nabla\times\mathbf F=0$. The components are $k_3-3=0$, $-k_1+4=0$ and $k_2-5=0$, giving $k_3=3$, $k_1=4$ and $k_2=5$.