GATE 2019 EE – Question 11
The inverse Laplace transform of $H(s)=\dfrac{s+3}{s^2+2s+1}$ for $t\ge0$ is
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Correct answer: (C) $2te^{-t}+e^{-t}$
Explanation
$\frac{s+3}{(s+1)^2}=\frac{(s+1)+2}{(s+1)^2}=\frac{1}{s+1}+\frac{2}{(s+1)^2}$, so $h(t)=e^{-t}+2te^{-t}$.