GATE 2015 EE – Question 38
The signum function is given by
$$sgn(x) = \begin{cases} \frac{x}{|x|}; & x \neq 0 \\ 0; & x = 0 \end{cases}$$
The Fourier series expansion of $sgn(\cos(t))$ has
Practise this question in The GATE Grind →
Show answer and explanation
Correct answer: (D) only cosine terms with odd numbered harmonics.
Explanation
$sgn(\cos t)$ is a square wave that is even about $t = 0$, so it contains only cosine terms. It also has half-wave symmetry, since shifting by half a period flips its sign, so only odd harmonics are present.