GATE 2017 EE – Question 12
For a complex number $z$, $\lim_{z \to i} \dfrac{z^2 + 1}{z^3 + 2z - i(z^2 + 2)}$ is
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Correct answer: (D) $2i$
Explanation
At $z = i$ both the numerator and the denominator are 0, so apply L'Hopital's rule. The derivative of the numerator is $2z = 2i$. The derivative of the denominator is $3z^2 + 2 - 2iz$, which at $z = i$ is $-3 + 2 + 2 = 1$. So the limit is $\frac{2i}{1} = 2i$.