GATE 2024 DA – Question 58
Consider two events T and S. Let $\bar{T}$ denote the complement of the event T. The probability associated with different events are given as follows: $P(\bar{T}) = 0.6$, $P(S|T) = 0.3$, $P(S|\bar{T}) = 0.6$.
Then, $P(T|S)$ is ______ (rounded off to two decimal places).
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Correct answer: 0.24 to 0.26
Explanation
$P(T) = 1 - 0.6 = 0.4$. By the total probability, $P(S) = 0.3 \times 0.4 + 0.6 \times 0.6 = 0.12 + 0.36 = 0.48$. By Bayes' theorem, $P(T|S) = \frac{P(S|T)P(T)}{P(S)} = \frac{0.12}{0.48} = 0.25$.