GATE 2024 CE (CE1) – Question 11
The smallest positive root of the equation $x^5 - 5x^4 - 10x^3 + 50x^2 + 9x - 45 = 0$ lies in the range
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Correct answer: (A) $0 < x \le 2$
Explanation
Group the terms: $x^4(x - 5) - 10x^2(x - 5) + 9(x - 5) = (x - 5)(x^4 - 10x^2 + 9) = (x - 5)(x^2 - 1)(x^2 - 9)$. The roots are $\pm 1$, $\pm 3$ and 5. The smallest positive root is 1, which lies in $0 < x \le 2$.