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GATE 2024 CE (CE2) – Question 41

Hydraulics · Channel hydraulics: specific energy, critical flow, uniform flow, hydraulic jump · 2 marks · Multiple choice

A round-bottom triangular lined canal is to be laid at a slope of 1 in 1500, to carry a discharge of 25 m$^3$/s. The side slopes of the canal cross-section are to be kept at 1.25H : 1V. If Manning's roughness coefficient is 0.013, the flow depth (in meters) will be in the range of

  1. 2.39 to 2.42
  2. 1.94 to 1.97
  3. 2.24 to 2.27
  4. 2.61 to 2.64

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Correct answer: (A) 2.39 to 2.42

Explanation

In the standard round-bottom triangular section the arc has the radius $y$ (equal to the depth), with its centre on the water surface, and the sides are tangent to it. The sides make the angle $\theta = \tan^{-1}\frac{1}{1.25} = 0.675$ rad with the horizontal. The area is $A = (\theta + 1.25)y^2 = 1.925y^2$ and the wetted perimeter is $P = (2\theta + 2.5)y = 3.849y$, so $R = \frac{A}{P} = 0.5y$. By Manning's equation $Q = \frac{1}{n}AR^{2/3}S^{1/2} = \frac{1}{0.013} \times 1.925y^2 \times (0.5y)^{2/3} \times \sqrt{\frac{1}{1500}} = 25$. This gives $y^{8/3} = 6.86$ and $y = 2.40$ m.