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GATE 2024 CH – Question 55

Process Calculations · Steady and unsteady state mass and energy balances · 2 marks · Numerical answer

Methane combusts with air in a furnace as $CH_4 + 2O_2 \to CO_2 + 2H_2O$. The heat of reaction $\Delta H_{rxn} = -880$ kJ per mol $CH_4$ and is assumed to be constant. The furnace is well-insulated and no other side reactions occur. All components behave as ideal gases with a constant molar heat capacity of 44 J mol$^{-1}$ °C$^{-1}$. Air may be considered as 20 mol% $O_2$ and 80 mol% $N_2$. The air-fuel mixture enters the furnace at 50 °C. The methane conversion $X$ varies with the air-to-methane mole ratio, $r$, as $X = 1 - 0.1e^{-2(r - r_s)}$ with $0.9r_s \le r \le 1.1r_s$ where $r_s$ is the stoichiometric air-to-methane mole ratio. For $r = 1.05r_s$, the exit flue gas temperature in °C, rounded off to 1 decimal place, is ______

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Correct answer: 1716.47 to 1733.73

Explanation

The stoichiometric air is $\frac{2}{0.2} = 10$ mol per mol of methane, so $r_s = 10$ and $r = 10.5$. The conversion is $X = 1 - 0.1e^{-2(0.5)} = 1 - 0.1 \times 0.3679 = 0.9632$. Per mole of methane fed, the heat released is $0.9632 \times 880000 = 847600$ J. The number of moles does not change in the reaction (3 mol in, 3 mol out), so the total is $1 + 10.5 = 11.5$ mol with a heat capacity of $11.5 \times 44 = 506$ J/°C. In the adiabatic furnace $\Delta T = \frac{847600}{506} = 1675.1$ °C, so the exit temperature is $50 + 1675.1 = 1725.1$ °C.