GATE 2022 ME (ME1) – Question 12
Solution of $\nabla^2T = 0$ in a square domain ($0 < x < 1$ and $0 < y < 1$) with boundary conditions: $T(x, 0) = x$; $T(0, y) = y$; $T(x, 1) = 1 + x$; $T(1, y) = 1 + y$ is
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Correct answer: (B) $T(x, y) = x + y$
Explanation
The function $T = x + y$ satisfies Laplace's equation (its second derivatives are zero) and it matches all four boundary conditions: $T(x, 0) = x$, $T(0, y) = y$, $T(x, 1) = x + 1$ and $T(1, y) = 1 + y$. The solution is unique.