GATE 2026 AE – Question 22
An $n \times n$ square matrix $A$ satisfies $A^T = A^{-1}$. The determinant of this matrix may take which of the following value(s)?
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Correct answer: (A) $+1$; (B) $-1$
Explanation
A matrix with $A^T = A^{-1}$ is orthogonal. Then $\det(A)\det(A^T) = \det(A)^2 = 1$, so $\det A = \pm 1$.