GATE 2021 BT – Question 20
Under standard T and P, 128 g of ideal gas A occupies 1 L and obeys $RT=0.25PV$. R is the universal gas constant. A is
Practise this question in The GATE Grind →
Show answer and explanation
Correct answer: (D) $O_2$
Explanation
**Ideal gas law:** $PV=nRT$.
**Step 1: use the given relation.** The problem gives $RT=0.25\,PV$. Substitute it into $PV=nRT$:
$$PV=n\,(0.25\,PV)\;\Rightarrow\;n=\frac1{0.25}=4\text{ mol}.$$
**Step 2: molar mass.** 128 g of the gas is 4 mol, so
$$M=\frac{128}{4}=32\text{ g/mol}.$$
- CO₂ = 44, H₂ = 2, N₂ = 28, **O₂ = 32**. ✓
Answer **O₂** (D).