GATE 2022 AE – Question 38
For $f_{xx}+f_{yy}=0$ and real separated solution $f=a(x)b(y)$, which statement can be true?
Practise this question in The GATE Grind →
Show answer and explanation
Correct answer: (C) a(x) is a periodic function and b(y) is an exponential function
Explanation
**Separation of variables.** For $f=a(x)\,b(y)$ in Laplace's equation $f_{xx}+f_{yy}=0$:
$$a^{\prime\prime}b+ab^{\prime\prime}=0\;\Rightarrow\;\frac{a^{\prime\prime}}{a}=-\frac{b^{\prime\prime}}{b}=-\lambda .$$
**Case $\lambda>0$:** $a^{\prime\prime}=-\lambda a$ gives sinusoidal $a(x)$ (periodic), and $b^{\prime\prime}=\lambda b$ gives exponential (hyperbolic) $b(y)$.
**Case $\lambda<0$:** the roles are swapped: $a(x)$ is exponential and $b(y)$ is periodic.
**Case $\lambda=0$:** both are linear.
The two factors can never both be periodic or both exponential, since the second derivatives must have opposite signs. Of the options, the one that can be true is **a(x) periodic and b(y) exponential** (C). Option A (periodic and linear) is impossible, since $\lambda=0$ makes both linear.