GATE 2026 CY – Question 40
With metal M and monodentate ligands L numbered as shown, the sigma ligand-group orbital with the same symmetry as $d_{z^2}$ in octahedral geometry is

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Correct answer: (A) $(2\sigma_1+2\sigma_2-\sigma_3-\sigma_4-\sigma_5-\sigma_6)/\sqrt{12}$
Explanation
The dz² orbital has equal-sign large axial lobes and opposite-sign equatorial amplitude. Normalization of coefficients 2,2,−1,−1,−1,−1 gives $1/\sqrt{12}$.