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GATE 2022 PH – Question 19

Mathematical Physics · linear differential equations: simple applications of first and second order linear differential equations and solutions · 1 mark · Multiple choice

$y^{\prime\prime}-2xy^\prime+4y=0$ has solution $y=a+bx+cx^2$. Which relation holds?

  1. $a=0,c=-2b\ne0$
  2. $c=-2a\ne0,b=0$
  3. $b=-2a\ne0,c=0$
  4. $c=2a\ne0,b=0$

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Correct answer: (B) $c=-2a\ne0,b=0$

Explanation

Substitute $y=a+bx+cx^2$ into $y^{\prime\prime}-2xy^\prime+4y=0$.

**Sum:**
$$2c+4a+(-2b+4b)x+(-4c+4c)x^2=(2c+4a)+2bx=0 .$$

For this to vanish for all $x$:
- the coefficient of $x$: $2b=0\Rightarrow b=0$,
- the constant: $2c+4a=0\Rightarrow c=-2a$.

So $c=-2a\neq0$ and $b=0$ (option B).