GATE 2020 ME (ME1) – Question 12
Evaluate $\displaystyle\lim_{x\to1}\frac{1-e^{-c(1-x)}}{1-xe^{-c(1-x)}}$.
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Correct answer: (C) $c/(c+1)$
Explanation
Both numerator and denominator vanish at x=1. Their derivatives are $-ce^{-c(1-x)}$ and $-(1+cx)e^{-c(1-x)}$. L’Hôpital’s rule gives **c/(c+1), C**, where c≠−1. The common exponential cancels.