GATE 2020 ME (ME2) – Question 12
A matrix P is decomposed into its symmetric part S and skew-symmetric part V. Given $S=\begin{pmatrix}-4&4&2\\4&3&7/2\\2&7/2&2\end{pmatrix}$ and $V=\begin{pmatrix}0&-2&3\\2&0&7/2\\-3&-7/2&0\end{pmatrix}$, find P.
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Correct answer: (B) $\begin{pmatrix}-4&2&5\\6&3&7\\-1&0&2\end{pmatrix}$
Explanation
By definition $S=(P+P^T)/2$ and $V=(P-P^T)/2$, so P=S+V. Add entrywise to obtain $P=\begin{pmatrix}-4&2&5\\6&3&7\\-1&0&2\end{pmatrix}$. This is **B**. S−V would instead reconstruct Pᵀ.