GATE 2020 ME (ME2) – Question 37
For $f(z)=x^3-3xy^2+iv(x,y)$, with $z=x+iy$ and $i=\sqrt{-1}$, which v makes f analytic?
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Correct answer: (D) $(3x^2y-y^3)+\text{constant}$
Explanation
Cauchy–Riemann gives vy=3x²−3y² and vx=6xy. Integrate the first equation: v=3x²y−y³+g(x). The second implies g′=0. Thus **v=3x²y−y³+constant,D**, consistent with f=z³+iC.