GATE 2026 MT – Question 12
Select the correct pair of eigenvectors for the symmetric matrix $$A=\begin{bmatrix}1&2\\2&4\end{bmatrix}.$$
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Correct answer: (A) $\begin{pmatrix}1\\2\end{pmatrix}$ and $\begin{pmatrix}-2\\1\end{pmatrix}$
Explanation
Multiplying gives $A(1,2)^T=(5,10)^T=5(1,2)^T$, so the first vector in A has eigenvalue 5. Also, $A(-2,1)^T=(0,0)^T=0(-2,1)^T$, so the second has eigenvalue 0.
Both are nonzero and mutually perpendicular, as expected for distinct eigenvalues of a real symmetric matrix. The correct pair is **A**.