GATE 2018 ME (ME2) – Question 14
If $y^3\frac{dy}{dx}+x^3=0$ with $y(0)=1$, find $y(-1)$.
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Correct answer: (C) 0
Explanation
Separate variables: $y^3\,dy=-x^3\,dx$. Integration gives $y^4+x^4=C$. Since $y(0)=1$, C = 1. At x = −1, $y^4=0$, hence **y = 0, C**.