GATE 2017 CE (CE2) – Question 38
Given $$A=\begin{bmatrix}1&5\\6&2\end{bmatrix},\quad B=\begin{bmatrix}3&7\\8&4\end{bmatrix},$$ find $AB^T$.
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Correct answer: (A) $$\begin{bmatrix}38&28\\32&56\end{bmatrix}$$
Explanation
Transpose B, then multiply in the stated order: $$B^T=\begin{bmatrix}3&8\\7&4\end{bmatrix},\quad AB^T=\begin{bmatrix}3+35&8+20\\18+14&48+8\end{bmatrix}=\begin{bmatrix}38&28\\32&56\end{bmatrix}.$$ Answer A.