GATE 2016 ME (ME3) – Question 5
S, M, E and F are working in shifts in a team to finish a project. M works with twice the efficiency of others but for half as many days as E worked. S and M have 6 hour shifts in a day, whereas E and F have 12 hours shifts. What is the ratio of contribution of M to contribution of E in the project?
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Correct answer: (B) 1:2
Explanation
Work equals efficiency multiplied by time. M has twice E’s efficiency, works half as many days and half as many hours per day. Hence M/E=2×(1/2)×(1/2)=1/2, so **M:E=1:2, B**.