GATE 2014 CS (CS1) – Question 57
f is continuous on [0,2], with f(0) = f(2) = −1 and f(1) = 1. Which statement must be true?
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Correct answer: (A) Some y in (0,1) satisfies f(y) = f(y+1).
Explanation
Define g(y)=f(y)−f(y+1) on[0,1]. It is continuous, with g(0)=−2 and g(1)=2. The intermediate value theorem guarantees an interior zero, so f(y)=f(y+1) for some y∈(0,1), **A**. Symmetry and a global maximum of1 are not implied.