GATE 2024 EC – Question 31
In the given circuit, the current $I_x$ (in mA) is ______.
Practise this question in The GATE Grind →
Show answer and explanation
Correct answer: 2
Explanation
Let the left node be A. The 1 kΩ on the left carries $I_0=V_A/1\text{k}$. The dependent source (− on the left, + on the right) gives $V_B=V_A+1000I_0=2V_A$. The middle branch is a 1 kΩ in series with a 2 mA current source, so it carries exactly 2 mA. KCL at A: the current into the dependent source branch is $5-I_0$. KCL at B: $5-I_0=2+I_x$, where $I_x=V_B/1\text{k}=2I_0$. So $5-I_0=2+2I_0$, giving $I_0=1$ mA and $I_x=2$ mA.