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GATE 2014 EC (EC1) – Question 23

Analog Circuits · Op-amp Circuits · 1 mark · Numerical answer

For the low-pass filter shown, find R₂ (kΩ) for a cutoff frequency of 5 kHz.

Diagram for GATE 2014 EC (EC1) question 23

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Correct answer: 3.1 to 3.26

Explanation

The inverting low-pass feedback impedance is R2/(1+sR2C), so the pole frequency is fc=1/(2πR2C). With C=10nF and fc=5000Hz, R2=1/(2π×5000×10⁻⁸)=3183.10Ω=**3.1831kΩ**. The input resistor sets the low-frequency gain, not this pole.