GATE 2014 EC (EC2) – Question 6
Find the odd group of letters.
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Correct answer: (C) W,C,G,J
Explanation
Using cyclic alphabet positions, Q→W→Z→B has gaps6,3,2. B→H→K→M and M→S→V→X have the same gaps. W→C→G→J instead has gaps6,4,3. Therefore **W,C,G,J,C** is the odd group.