GATE 2014 EC (EC2) – Question 13
For $0\le t<\infty$, where does $f(t)=e^{-t}-2e^{-2t}$ attain its maximum?
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Correct answer: (A) $t=\ln4$
Explanation
Differentiate:f′=−e⁻ᵗ+4e⁻²ᵗ. Setting this to zero gives eᵗ=4, so t=ln4. The derivative is positive before this point and negative afterwards; equivalently the second derivative there is negative. Hence the maximum occurs at **t=ln4,A**.