GATE 2014 EC (EC4) – Question 5
In a sequence of 12 consecutive odd numbers, the sum of the first five is 425. Find the sum of the last five.
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Correct answer: 495 to 495
Explanation
Let the first odd number be a. The first five sum to5a+2(0+1+2+3+4)=5a+20=425, giving a=81. The last five are terms8through12, with offsets14,16,18,20,22. Their sum is5×81+90=**495**.