GATE 2014 EE (EE2) – Question 27
A system has closed-loop $T(s)=4/(s^2+0.4s+4)$. Find steady-state error to a unit step.
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Correct answer: 0 to 0
Explanation
The poles of s²+0.4s+4have negative real parts,so the final-value theorem applies. For a unit step,y∞=T(0)=4/4=1. The tracking error r−y therefore tends to1−1=**0**. Use the supplied closed-loop transfer directly rather than treating it as an open-loop function.