Writing everything as a power of 3, $3^{x^2} = 3^3 \times 3^{2x} = 3^{3 + 2x}$, so $x^2 = 2x + 3$, that is $x^2 - 2x - 3 = 0$ and $x = 3$ or $x = -1$. The expression is $\frac{2^{x^2}}{2^{2x}} = 2^{x^2 - 2x} = 2^3$, since $x^2 - 2x = 3$ for both roots.
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