A 150 mm wide polyamide flat belt transmits 15 kW. Driving-pulley pitch diameter is 150 mm and speed 200 rpm. Find tight-side minus slack-side tension in N to one decimal.
Belt speed is $v=\pi DN/60=\pi(0.15)(200)/60=1.5708$ m/s. Power = (F₁−F₂)v, so $\Delta F=15000/1.5708=\mathbf{9549.3}$ N. Belt width is not needed for the tension difference.
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