The GATE Grind

GATE Metallurgical Thermodynamics: Reaction equilibria and Ellingham diagrams – Previous Year Questions

10 GATE previous year questions on Reaction equilibria and Ellingham diagrams (Metallurgical Thermodynamics, Metallurgical Engineering) with answers and explanations, from every paper.

  1. GATE 2021 MT Q53 (2 marks, Numerical answer) – For 2Cu(s)+SO 2(g) Cu 2S(s)+O 2(g) at 973 K, (p O 2/p SO 2)= (two decimal places). Given G=-100 kJ for 2Cu(s)+0.5S 2(g) Cu 2S(s) and G=292 kJ for SO…
  2. GATE 2022 MT Q12 (1 mark, Multiple choice) – By Sieverts’ law, the equilibrium solubility of nitrogen gas in molten steel is proportional to . Its equilibrium partial pressure is p N 2.
  3. GATE 2022 MT Q48 (2 marks, Numerical answer) – Find the equilibrium ratio p CO/p CO 2 at 1873 K for the reaction Mo(s)+ O 2(g)MoO 2(s) (two decimal places). Given: fG 1873=-262300 J, a MoO 2=0.5,…
  4. GATE 2023 MT Q14 (1 mark, Multiple choice) – At one atmosphere, iron and nickel oxidise according to: 2Fe+ O 22FeO, G=-527400+128T J. 2Ni+ O 22NiO, G=-471200+172T J. Temperature T is in kelvin.…
  5. GATE 2025 MT Q19 (1 mark, Multiple choice) – Consider the gas-phase reaction 2SO 2+ O 22SO 3. If its enthalpy of reaction is negative, which condition promotes a higher equilibrium concentration…
  6. GATE 2025 MT Q30 (1 mark, Multiple select) – Standard Gibbs free energies of formation of solid oxides per mole of O 2 at 1000 K are: SiO 2: −728 kJ; TiO 2: −737 kJ; VO: −712 kJ; MnO: −624 kJ.…
  7. GATE 2025 MT Q34 (1 mark, Numerical answer) – For the gas-phase reaction CO+12 O 2CO 2, equilibrium partial pressures at a particular temperature are p CO=10-6 atm, p O 2=10-6 atm, and p CO 2=16…
  8. GATE 2025 MT Q51 (2 marks, Numerical answer) – Molten steel at 1900 K containing dissolved hydrogen must be vacuum degassed. The equilibrium hydrogen partial pressure needed to achieve 1 ppm (mass…
  9. GATE 2025 MT Q53 (2 marks, Numerical answer) – Consider the reactions and standard Gibbs free energies (J): Fe(s)+12 O 2(g)FeO(s), G=-264900+65T. 2 H 2(g)+ O 2(g)2 H 2O(g), G=-492900+109T. Assume…
  10. GATE 2026 MT Q56 (2 marks, Numerical answer) – With reference to the Ellingham diagram, the standard Gibbs free-energy changes for oxidation of solid and liquid metal M are: Reaction I: M(s)+O 2(g)…