Trace is invariant under cyclic permutations, giving three members. Reversal is not generally valid: take A₁=E₁₁,A₂=E₁₂,A₃=E₂₁. Original product has trace 1, while A₁A₃A₂ has trace 0. All three noncyclic permutations are cyclic rotations of that reversed order, so all fail. **3**.
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