The displayed u is Re(e^(2z)sin3z), so f=e^(2z)sin3z+2i. At z=iπ, e^(2iπ)=1 and sin(3iπ)=i sinh3π. Hence 4+2if(iπ)=4−2(sinh3π+2)=−2sinh3π=**−e^(3π)+e^(−3π), C**.
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